[PSA] Chapter 6 - Generator modeling I (Machine Viewpoint)
6.1 Classical Machine description
- Rotor or field : Rotating part
- Stator : Stating part
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6.2 Voltage generation
- Basic assumptions : neglect resistance, considering only air-gap flux
- Magnetic circuit is linear
- Flux density $\mathbf B$, in the air gap, due to $i_F$ alone, is radial and has a spatial distribution as a function of angle given by
- The direction is outward
- Each coil consists of $N$ turns concentrated in a single slot.
- $\theta$ : angle the rotor axis (North pole) is looking at
- $\alpha$ : general angle we are looking at
6.3 Open circuit voltage
- with zero current in stator, only the rotor field current $i_F$ produces air-gap flux
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- Flux in crosshatched rectangular slot at an angle $\alpha$ is
- Then, integrate to get flux over all Gaussian surface
- Denote $\phi_{max} \triangleq 2 \ell r B_{max}$
- Flux linkage of coil $aa’$
- Other phases are similar with only changing its phase by $\pm 120 ^\circ$
- Rotor rotates with given angular frequency, we can assume
- Also, By Faraday’s law, the EMF induced :
- We can say Voltage imposed at the stator $e$ lags $\lambda$ by $90 ^\circ$
- Also, define effective phasor
- Define effective Voltage
6.4 Armature Reaction
- Armature (Balanced three-phase stator) current produce own rotating magnetic field
- Armature reaction flux linkage representaged by equivalent inductance
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- Skip for now *
6.5 Terminal Voltage
- Total air-gap flux is sum of rotor-field flux and armature-reaction flux.
- Differentiating every flux to get terminal voltage
- Account for windings resistance or leakage inductance ($r, X_l$)
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- Resolve Phasors $I_a, I_b, I_c$ into two groups of components
- Direct axis of the rotor $I_{ad}, I_{bd}, I_{cd}$
- Quadrature axis direction of the rotor $I_{aq}, I_{bq}, I_{cq}$
- Assume that $\phase{I_a} = \theta_0 \pm 90^\circ$, Where stator current (phase a) is perpendicular to Voltage or EMF
- Also can divide $\Lambda_{ar}$ into two terms
- Define fictitious inductance parameters
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- Multiply by $-j\omega_0$ and substitute (6.26) to remove flux linkage
- Consider $r, X_l$
- Substitute two equations above
Where $X_d \triangleq X_{d1}+X_l$, $X_q \triangleq X_{q1}+X_l$
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- We can show $a’$ and $E_a$ are colinear by getting difference
6.6 Power Delivered by Generator
Round rotor
- Neglecting resistance for a round rotor,
Salient-pole generator
- Also neglecting resistance,
- We can substitute equations to (6.30)
- Dividing into real and imaginary axis,
- We can express $I_{aq}, I_{ad}$
- Substitute into $S_G$ to get $P_G, Q_G$
- If $X_d = X_q = X_s$, the second term cancels
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6.7 Synchronizing Generator to an infinite bus
- Definition : An infinite bus is an ideal voltage source
- Frequency is the same
- Phase sequence, Phase is the same
- $\vert V_a \vert = \vert E_a \vert = \vert V_\infty \vert$
- If this happens, $I_a = 0, S_G=0$ (Floating)
- When turbine accelerates, $\delta_m = \phase{E_a} - \phase{V_\infty}$ increases, thus $P_G$ increases
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- To keep mechanical power constant, $\vert E_a \vert \sin\delta_m=\text{constant}$
- $E_a$ must be located in dotted line, increasing $\delta_m$ decreases $i_F$ (proportional to length of $E_a$)
6.8 Synchronous condencer
- $\delta_m = 0 \Rightarrow P_G=0$ (Unloaded)
- But it delivers reactie power.
- Generator but specifically built to operate in this mode is called synchronous condencer
- Convinent and continuous control of reactive power by adjusting the field current $i_F$
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